0.0072v^2+0.19v-38=0

Solution for 0.0072v^2+0.19v-38=0 equation:

0.0072v^2+0.19v-38=0

a = 0.0072; b = 0.19; c = -38;
Δ = b2-4ac
Δ = 0.192-4·0.0072·(-38)
Δ = 1.1305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.19)-\sqrt{1.1305}}{2*0.0072}=\frac{-0.19-\sqrt{1.1305}}{0.0144}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.19)+\sqrt{1.1305}}{2*0.0072}=\frac{-0.19+\sqrt{1.1305}}{0.0144}
$